3x+[1-3(x+2)]=2x

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Solution for 3x+[1-3(x+2)]=2x equation:


Simplifying
3x + [1 + -3(x + 2)] = 2x

Reorder the terms:
3x + [1 + -3(2 + x)] = 2x
3x + [1 + (2 * -3 + x * -3)] = 2x
3x + [1 + (-6 + -3x)] = 2x

Combine like terms: 1 + -6 = -5
3x + [-5 + -3x] = 2x

Remove brackets around [-5 + -3x]
3x + -5 + -3x = 2x

Reorder the terms:
-5 + 3x + -3x = 2x

Combine like terms: 3x + -3x = 0
-5 + 0 = 2x
-5 = 2x

Solving
-5 = 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-5 + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
-5 + -2x = 0

Add '5' to each side of the equation.
-5 + 5 + -2x = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -2x = 0 + 5
-2x = 0 + 5

Combine like terms: 0 + 5 = 5
-2x = 5

Divide each side by '-2'.
x = -2.5

Simplifying
x = -2.5

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